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[build] Use $(shell ...) to invoke BUILD_ID_CMD 

When using $(shell), make will first invoke BUILD_ID_CMD and then have
the value defined when calling $(LD).  This means we get to see the
_build_id when building with make V=1.  Previously the build_id was
figured out as a subshell command run during the recipe execution
without being able to see the build_id itself.

Signed-off-by: Michael Brown <mcb30@ipxe.org>
pull/242/head
Manuel Mendez 2021-01-29 09:23:54 -05:00 committed by Michael Brown
parent 9d000c9fd7
commit bc4979e2cf
1 changed files with 1 additions and 1 deletions
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2
src/Makefile.housekeeping
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@ -1199,7 +1199,7 @@ $(BIN)/version.%.o : core/version.c $(MAKEDEPS) $(GIT_INDEX)
$(BIN)/%.tmp : $(BIN)/version.%.o $(BLIB) $(MAKEDEPS) $(LDSCRIPT)
$(QM)$(ECHO) " [LD] $@"
$(Q)$(LD) $(LDFLAGS) -T $(LDSCRIPT) $(TGT_LD_FLAGS) $< $(BLIB) -o $@ \
--defsym _build_id=`$(BUILD_ID_CMD)` \
--defsym _build_id=$(shell $(BUILD_ID_CMD)) \
--defsym _build_timestamp=$(BUILD_TIMESTAMP) \
-Map $(BIN)/$*.tmp.map
$(Q)$(OBJDUMP) -ht $@ | $(PERL) $(SORTOBJDUMP) >> $(BIN)/$*.tmp.map